Sunday, September 12, 2010

The notes from sections 8-1 and 8-2.

In section 8-1 we are solving for (theta), to solve for (theta) you have to get the trig function by itself and then take the inverse of it.
- an inverse has two answers with some exceptions, find some exceptions, findwhere the angle is based on the trig function and if the number is positive or negative.

Steps:
1. take the inerse of the positive number to find the Q1 angle to get this
Q2: make negative degrees and add 180 degrees.
Q3: Add 180 degrees.
Q4: Make negative degrees and add 360 degrees.

Ex 1:
Solve sin x= -6 for x
x= sin-1 (.6)
x= 36.870, 143.130 degrees

8.2
In this section you are graphing the period changes of sine and cosine.

- y= Asin Bx or y= A cos Bx
- absolute value of {A} = amplitude
-2(pie)= Period

Steps:
Take all 5 points (0, (pi)/2, (pi), 3(pi)/2, 2(pi))
- divide by B
-Sketch the graph

Ex
y=4sin3x
amp: l4l = 4
Pi/6period: 2pi/3 =2pi/3

Now by dividing 0, pi/2, pi, 3pi/2, & 2pi by 3, you get these 5 points.
0/3= 0
pi/2/3= pi/6
pi/3= pi/3
3pi/2/3= pi/2
2pi/3=2pi/3

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