Taylor's 8th(or 9th I don't know XD) Blog

The following is part three of my notes on lesson 9.1.

For this lesson we will only be using right triangles . We will be using Tan for these problems as well and only Tan for part 3 of this lesson.

To find Tan remember this:

Tan Theta = opposite/adjacent

(REMEMBER I DO NOT KNOW HOW TO PUT PICTURES ON THIS BLOG SO JUST DO AS I SAY AND REMEMBER THAT THE LENGTH OPPOSITE OF THE ANGLE IS THE LOWER CASE LETTER OF THAT ANGLE)

Triangle ABC is a right triangle. Use the following information to solve for it.

A=90 degrees a= 60
B= 40 degrees b=40
C= 50 degrees c=?

First, draw your triangle with the information that I gave you includes.

Tan 40= 40/? Then, write out your equation like the formula I gave you.

Tan 40 x ?= 40 Then you would multiply by ? And get this as your answer.

c= 47.670 Finally, just divide by Tan 40 both sides, round to the third place after the decimal and you get this as your answer.

Triangle ABC is a right triangle. Use the following information to solve for it.

A=90 degrees a= 5
B= ? degrees b=4
C= ? degrees c=2

First, draw your triangle with the information that I gave you includes.

Tan C= 2/4 Then, write out your equation like the formula I gave you.

C= Tan^-1 (2/4) Then, you need to find the inverse.

C= 26.565 degrees Then, solve and round to the third place after the decimal. Then, you would normally need to make sure that there is no other possible angle but since the positive form of
Tan is on the first and third quadrant, you cannot do it for the third quadrant is up to 270 degrees and triangles can only go up to 180 degrees so this is your only answer.

180 degrees -90 degrees -26.565 degrees= 63.435 degrees Finally, you just have to subtract 90 degrees and 26.565 degrees from 180 degrees and you will get 63.435 degrees for angle B.

So your answers will be C= 26.565 degrees and B= 63.435 degrees.

THAT IS ALL FOR THIS PART OF MY LESSON 9.1 PART 2 NOTES !! SO UNTIL NEXT TIME JA NE!!!! (ja ne is goodbye in Japanese)