Taylor's 6th Blog (i think lol)

The following is part one of my notes on lesson 9.1.

For this lesson we will only be using right triangles . We will be using Sin for these problems as well and only Sin for part 1 of this lesson.

To find Sin remember this:

Sin Theta = opposite/ adjacent

(REMEMBER I DO NOT KNOW HOW TO PUT PICTURES ON THIS BLOG SO JUST DO AS I SAY AND REMEMBER THAT THE LENGTH OPPOSITE OF THE ANGLE IS THE LOWER CASE LETTER OF THAT ANGLE)

Triangle ABC is a right triangle. Use the following information to solve for it.

A=90 degrees a= 5
B= 20 degrees b=6
C= 70 degrees c=?

First, draw your triangle with the information that I gave you includes.

Sin 70= ?/5 Then, write out your equation like the formula I gave you.

c= 4.698 Finally, just multiply five on both sides, round to the third place after the decimal and you get this as your answer.

Triangle ABC is a right triangle. Use the following information to solve for it.

A=90 degrees a= 5
B= ? degrees b=4
C= ? degrees c=3

First, draw your triangle with the information that I gave you includes.

Sin C= 3/5 Then, write out your equation like the formula I gave you.

C= Sin^-1 (3/5) Then, you need to find the inverse.

C= 36. 870 degrees Then, solve and round to the third place after the decimal. Then, you need to make sure that the other possible angle cannot be used so turn the answer into a negative and add 180 degrees. You should get 143.13 degrees. Then, add 90 degrees to it and you get 233.13. Since this is over 180 degrees we cannot use it for triangles only have 180 degrees in them.

180 degrees -90 degrees -36. 870 degrees= 53.13 degrees Finally, you just have to subtract 90 degrees and 36. 870 degrees from 180 degrees and you will get 53.13 degrees for angle B.

So your answers will be C= 36. 870 degrees and B= 53.13 degrees.

THAT IS ALL FOR THIS PART OF MY LESSON 9.1 PART 1 NOTES !! SO UNTIL NEXT TIME JA NE!!!! (ja ne is goodbye in Japanese)