so aleks thinks i'm stupid and wants to know if i can add fractions with common denominators. its SUPER difficult...(sarcasm) so here are some steps and an example for you slow folk. and i actually think i got a negative wrong on the assesment and had to do this module again! its really simple i promise. i would go over what ya'll did friday but i wasn't here and someone should really give me the notes tomorrow.
Problem: (4v-3w)/6v-(9v+5w)/6v
Each fraction has the same denominator, namely
So we subtract the numerators and keep the denominator the same to get
(4v-3w)-(9v+5w)
----------------------
6v
Distributing the negative sign over the parentheses, we have
4v-3w-9v-5w
-----------------
6v
Combining like terms, we get
-5v-8w
---------
6v
This fraction cannot be simplified so that's the answer. have fun.
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