The notes that I will go over are a combination of section 8-1 and 8-2.
These are the formulas:
m=tan (alpha) for a line
tan 2(alpha)=B/A-C if A does not = C for a conic
(alpha)=π/4 if A = C for a conic
Ax^2+Bxy+Cy^2+Dx+Ey+F=0
Ex. Find the inclination of the line to the nearest degree: 6y=2x+12
Now, you have to find slope by solving for y:
y=1/3x+2
m=1/3
1/3=tan (alpha)
(alpha)=tan^-1 (1/3)
(alpha)=18.435
Now you have to find which quadrants tan is positive in: Q I and III
You already have Q I.
To get to quadrant III, you have to add 180.
18.345+180=198.345
(alpha)=18.345 degrees and 198.345 degrees.
I understood most of the concepts from chapter 8, but you have to pay close attention to fully understand it. I am probably going to have to work more problems in the book. A special tribute goes out to all of the victims and families of the 9/11 tragedy. GOD BLESS AMERICA
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