The following is part one of my notes on lesson 6.2.
In this lesson we will be learning a few new things about circles.
You will need these equations in order to do this properly:
Distance formula= square root (y2-y1)^2+(x2+x1)^2= radius
The 2 and ones are small and are at the bottom to symbolize that they are from either the first and second point . One of these points must be the center while the other must be on the circle.
Equation of a circle (x-h)^2+(y-k)^2=r^2 the (h,k) is the center of the circle.
Now lets practice how to find the radius and the center of the circle from the equation of the circle. Which is also the easiest and simplest part to do for this chapter.
Find the center and the radius of (x-9)^2+(y-8)^2=16.
From the equation of the circle we can see that the place where 9 and 8 are is replacing the h and the k so that means that the center of the circle is (9,8).
We also know that the radius is raised to the second before it can be considered part of the equation so we just need to find the square root of 16 in order to find the radius. So that makes the radius 4.
Find the center and the radius of (x+5)^2+(y+11)^2=15.
From the equation of the circle we can see that the place where 5 and 11 are is replacing the h and the k but since they are not negative we have to make them negative when we write it in coordinate form. So the center of the circle is (-5,-11)
We also know that the radius is raised to the second before it can be considered part of the equation so we just need to find the square root of 15 in order to find the radius but since we cannot we will simply leave it with the square root as the answer. So that makes the radius square root of 15.
THAT IS ALL FOR THIS PART OF MY LESSON 6.2 NOTES !! SO UNTIL NEXT TIME JA NE!!!! (ja ne is goodbye in Japanese)
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