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Dom's blog

I don't know about those guys but i thought this week was pretty awesome, we got to get credit for easy tests every day, catch up on our aleks, and have some fun. My favorite was probably the chapter seven test because it was the easiest one to do. I'm surprised I still remember that trig chart. Well thats it...peace.

Nathan's blog

This week in advanced math, we basically did a bunch of aleks. Monday we had SAT's and everyone else went on a field trip. Then the rest of the week we started on chapter 6, and on thursday and friday, we did aleks with the sub. Chapter 6 had to deal with equations of circles and ellipses, and stuff like that. I checked out on wednesday and missed a little bit of the lesson but i should be able to pick up on it pretty fast. That is all for this blog.

mary'ss blog

this. week. was. crazy. We had to sell candy and get ready for state, and we did aleks, alot of them, and then we couldn't do work because brob left us. haha. But dang, all them aleks really helped during everything i did at state, especially the game descartes. i swear i wouldn't have known half the stuff i knew without it. i really like math club, it's really fun and worth it, i can't even imagine not being in it at this point:)) this question came up on a 10 point card in how many zeros does 127! end! ahahahah!!!!!!!!!!1

Nicala's Post

this week we did not really get to do anything. because of the sat and the field trip and then thing with mu alpha theta. so we mainly did aleks the whole week. Which most of them i did not know what i am doing so i get put out or i fail my assestment and have to do the same things over and over. okay so i am going to back to chapter 13 section 1. In this chapter they are talking about sequences. A sequences is a set of number. There are two different type of sequences we learn about in this section, arithmetic and geometric. I am only talking about arithmetic because i am sleeping and ready to go to bed lol :) Arithmetic squence is when you add the same number to every term. The only formula you need to know for this problem is tn=t1+(n-1)d. d is the number that you are adding to each term. Example Problem Find the first four terms of this equation 7n+2. in the problem you always replace n with number term you are on. t1=7(1)+2=9 t2=7(2)+2=16 t3=7(3)+2=23 t4=7(4)+2=30 So the first four terms in this equation is 9,16,23,30

Lawrence's blog

this week was really crazy. we couldnt really do much in the class because of the SAT and people that were in mu alpha theta. so really all we did was Aleks. i didnt know how to do any of the ones that we had to do. i attempted even copied the problems and tried workign them step for step and still couldnt get them. so i guess im screwed till it makes me take a dumb 30 question test. if there is anyone who is below me and may need my help i can help you with it and hopefully for some odd reason someone will know how to do the stuff im on

Another One Of Taylor's Blogs

The following is part one of my notes on lesson 6.3.

In this lesson we will be doing the easier parts of finding the parts of the equation.

The one we will be doing are in this form

x^2/a+y^2/b=1

We will by finding the minor and major axis and the length of the major and minor axis.

Equations
Length of major 2 square root of lager denom.
Length of minor 2 square root of smaller denom.

Lets do some example problems

Find the minor and major axis and the length of the major and minor axis of x^2/9+y^2/25=1

First we will identify the major and minor axis. In this case the major axis is y and the minor axis is x.

2 square root of 25= 2 x 5= 10 Then we simply plug the major axis’s denominator into this equation and solve it to find the length of the major axis.

2 square root of 9= 2 x 3= 6 Then we simply plug the minor axis’s denominator into this equation and solve it to find the length of the minor axis.

And your answers will be major axis= y, minor axis= x, length of the major axis= 10, length of the minor axis= 6. Lets do one more!

Find the minor and major axis and the length of the major and minor axis of x^2/81+y^2/36=1

First we will identify the major and minor axis. In this case the major axis is x and the minor axis is y.

2 square root of 81= 2 x 9= 18 Then we simply plug the major axis’s denominator into this equation and solve it to find the length of the major axis.

2 square root of 36= 2 x 6= 12 Then we simply plug the minor axis’s denominator into this equation and solve it to find the length of the minor axis.

And your answers will be major axis= x, minor axis= y, length of the major axis= 18, length of the minor axis= 12.

THAT IS ALL FOR THIS PART OF MY LESSON 6.3 NOTES !! SO UNTIL NEXT TIME JA NE!!!! (ja ne is goodbye in Japanese)